⇒ x = 720° – 4x One obtuse angle and one acute angle can make a pair of supplementary angles. ∴ a + b = c [Alternate interior angles] Thus, ∠x = 60°, ∠y = 120°and ∠z = 60°, Question 92. (c) a is false and b is true Its complement -90° – x In the given figure, ∠AOC and ∠BOC form a pair of Hence, ∠a = 30°, ∠b = 150°, ∠c = 150°. asked Jun 2 in Lines and Angles by Subnam01 (52.0k points) lines and angles; class-7; 0 votes. ∴ ∠COF = ∠EOD = 110° [Using (i)] [Vertically opposite angles] ∴ ∠POR + ∠ROT + ∠TOQ = 180° ⇒ ∠2 = 70° ——— (ii) Complementary angles: Two angles that add up to 90° (or a right angle) are complementary. ∴ ∠PQR – ∠QRS = 85° ———– (i) [Alternate interior angles] Measures (in degrees) of two supplementary angles are consecutive odd integers. ∴ ∠QOS = 5 ∠POR = 5 × 15° = 75°, Question 23. False. In figure, OB is perpendicular to OA and ∠BOC = 49°. (ii) ∠POS and ∠SOQ; ∠POR and ∠ROQ are two pairs of supplementary angles. ∴ ∠3=68° ——– (i) [Corresponding angles] (a) ∠TOS and ∠SQR is a pair of complementary angles. (a) Seven football players are practicing their kicks. ⇒ 130° + y = 180° Two adjacent angles always form a linear pair. Question 110. But the angles don’t have to be together. Question 103. l || n and q is a transversal. False (c) Since, PQ || RS and line 1 is a transversal. Which player has the best kicking angle? (b) 50°,130° ⇒ ∠POR + ∠QOS = 180° – 90° = 90° ——- (i) and its supplement = 180° – x= 180°- 100 = 80° Since, AB || l and EF is a transversal. (d) 105°, 75° Solution: ∴ The angles between North and West and South and East are supplementary. \(\Rightarrow x=\frac{120^{\circ}}{2}=60^{\circ}\) (c) 79° Solution: (c) Estimate atleast two situations such that the angles formed by different positions of two players are complement to each other. Solution: False Two angles are Complementary when they. In the given figure, POR is a line. (b) 90° (b) Since, POQ is a straight line Thus, the required angles are 60° and 30°. (∵ 45° + 45° = 90° and 60° + 30°= 90°). (a) 130° 1.Two angles that are complementary never form a linear pair. So an angle of 30° has a supplementary angle of 90° - 30° = 60°. But the angles don't have to be together. Solution: Solution: ∴ ∠PTR – ∠TRU= 42° ——— (i) [Alternate interior angles] (a) Since, POQ is a straight line. (d) 120° (d) ∠2 + ∠3 = 180° (c) 80° (a) 126° The angle which makes a linear pair with an angle of 61° is of and ∠y + 35° = 180° [Co-interior angles] What is the degree measure of the larger angle? (d) 45°, 45° Find the value of a + b. You can specify conditions of storing and accessing cookies in your browser. (b) complementary Thus, one angle is 45° and other is 180° – 45° = 135°, Question 98. Interior angles on the same side of a transversal with two distinct parallel lines are complementary angles. Name; One obtuse angle and one acute angle can make a pair of complementary angles. Solution: Then, f is equal to Complementary angles are two angles that add up to 90°, or a right angle; two supplementary angles add up to 180°, or a straight angle. Question 86. ∴∠CHE = ∠HCB – 120° ———- (i) [Alternate interior angles] Question 60. ⇒ ∠b = 180° – 30° = 150° [Using (1)] 2. Also, m || n and p is transversal. Acute, Question 54. (c) 5° One obtuse angle and one acute angle can make a pair of complementary angles. (b): Since, vertically opposite angles are equal. Answer. ∠FOR + ∠QRH = 123° + 57° = 180° Then, angles a and bare respectively In the given figure, l, m and n are parallel lines, and the lines p and q are also parallel. Explanation: Angle equal to 90 o is called right angle. Its complementary angle must be less than 45°. (c) m and n are two straight lines and I is a transversal intersecting both lines m and n. (d) Since, sum of the angles about a point is 360° 2x + 1 + 2x + 3 = 180° Proof The supplement of the right angle is always _________ angle. ∴ ∠1 = ∠2 [Alternate interior angles] (b) (3 – 6)° (c) ∠1 and ∠3; ∠2 and ∠4 are the two pairs of vertically opposite angles. We know that the sum of the measures of the complementary angles is 90° Maths MCQs for Class 7 Chapter Wise with Answers PDF Download was Prepared Based on Latest Exam Pattern. In Parts (a) and (b) given below, it may help to trace the diagrams and draw and measure angles. Since, PQ || RS and TR is a transversal. \(\Rightarrow \quad b=\frac{120^{\circ}}{3}=40^{\circ}\) Solution: According to question, Distinct. ⇒ 50° + ∠QPR – 130° Question 25. ⇒ (3a + 5)° + (2a-25)° = 180° and x – y = 30° ——— (ii) [Given] Question 82. (a) 20° In the given figure, line l intersects two parallel lines PQ and RS. Thus, one angle is 100° and other is 80°. and b = 132° [Vertically opposite angles] Question 21. (ii) No, a and b are not adjacent angles as they don’t have common arm. If ∠x = ∠y = ∠z, then ∠x and ∠y; ∠y and ∠z; ∠z and ∠x are three pairs of complementary angles. In the given figure, the value of x is (b) 61° ∴ ∠RST + a = 180° [Linear pair] 0 0. ∴ ∠ABC + ∠BCD = 180° [Co-interior angles] because 90° + 90° = 180°, as it satisfies the condition of supplementary angles. (a) 125° If two angles add up to 180o they are _____ angles. Now, ∠PQR = ∠PQU + ∠UQR (d) 10° Solution: Solution: If two angles are complementary of each other, then each angle is: A. an obtuse angle. 3k + 2k = 90° ⇒ 5k = 90° As vertically opposite angles are always equal but do not form a linear pair. The angle The angles x and 90° – x are ⇒ ∠2 = 180° – 75° = 105° From (i) and (ii), we get ∴ Its complement = 90°- 45° = 45°, Question 56. (b) Now the players are lined up as shown in Fig. ⇒ ∠c = 180° – 30° = 150° (a) All (i), (ii) and (iii) are true Also, m || n and QR is a transversal. Question 18. Putting value of x in (i), we get (iv) c and f (i) ∠AOB and ∠BOC; ∠AOC and ∠COD; ∠AOB and ∠BOD; and ∠BOC and ∠COD are adjacent angles. ∴ b = 50° [Alternate interior angles]. ∴ ∠1 = 34° [Alternate interior angles] (d) 101° ∴ y = 180° – 80° = 100° \(\Rightarrow c=\frac{120^{\circ}}{4}=30^{\circ}\) ———– (i) z + y = 180° [Linear pair] ∠AOF=∠COD [Vertically opposite angles] (b) 60° ⇒ 2∠ABP = 180° – 46° = 134 q: a and b are forming a pair of adjacent angles. (c) 64° 2 angles are Complementary when they add up to 90 o (a Right Angle). Find ∠PQR. Solution: Supplementary angles and complementary angles are defined with respect to the addition of two angles. ∴ x + 2x = 180° Opposite, Question 49. The angles x – 10° and 190° – x are Yes, because the sum of two angles is 180, and if they are both 90 degrees, they add up to 180, making them supplementary, and of the same measure, making them congruent. (c) If one of the angles is right, then other angle of a linear pair is also right. Now, ∠BOC = (x + 5)° = (35 + 5) = 40° Now, l || m and p is a transversal. These angles aren’t the most exciting things in geometry, but you have to be able to spot them in a diagram and know how to use the related theorems in proofs. In the given figure, PQ is a mirror, AB is the incident ray and BC is the reflected ray. (a) Since, ∠P + ∠Q = 180° Question 1. Solution: Two angles making a linear pair are always adjacent angles. ∴ y + 48° = 180° [Co-interior angles] (b) PQ is a straight line. Question 89. These two angles (40° and 50°) are Complementary Angles, because they add up to 90°: Notice that together they make a right angle. (d) ∠a = ∠d Solution: These two angles (140° and 40°) are Supplementary Angles, because they add up to 180°: Notice that together they make a straight angle. Also, AB || DF and BD is a transversal. Question 78. (a) 110° A right angle measures 90°. ∴ Its supplement = 180° – x A pair of complementary angles is angl… Get the answers you need, now! We have, Solution: (a) 13 angles are formed. Solution: ⇒ y = 180° – 48° = 132° (a) Both statements p and q are true. (b) 50°, 20° ⇒ f = 108°, Question 37. (a) Let the two angles be x and 2x. ⇒ x + 4x = 720° In the given figure, if l || m, find the values of a and b. Question 32. Solution: If two angles add up to 90°, they are _____ angles. Find the values of a, b and c. True, Question 64. ⇒ ∠y = 180° – 35° = 145° Solution: \(\Rightarrow \quad x=\frac{176^{\circ}}{4}=44^{\circ}\) If the sum of measures of two angles is 90%, then the angles are _________ - one angle is 90° and all three add up to 180°. 3.Two angles that are congruent are sometimes right. 45° _____ 4. (a) Since, POR is a straight line. Give reason in support of your answer. The supplement of an acute is always _________ angle. ⇒ y = 90° – 60° = 30° (i) Yes, and b are the adjacent angles as they have a common vertex, one common arm and other non-common arms on the opposite side of the common arm. Solution: = 264° + 132° = 396°. ⇒ a = 180° – 85° = 95°. ∴ x + 66° = 180° [Co-interior angles] Thus, the angle which is half of its supplement is of 60°. False alternate interior angles have one common _________ Thus, a = 67° and b = 48°, Question 102. Arm, Question 47. ∴ x + 64° + 46° +100° – 360° The S in supplementary can be used to form the 8 in 180. In the given figure, write all the pairs of supplementary angles. 180°, Question 46. If an angle is 60° less than two times of its supplement, then the greater angle is Solution: Question 42. ⇒ 4 × 30° = 3b      [using (i)] Thus, ∠COF = 110°, Question 95. (b) 90°, 90° Question 6. As two right angles are supplementary to each other. In the given figure, state which pair of lines are parallel. (c) one of its angles is right? Question 87. Also, PQ || RS and line I is a transversal. ⇒ ∠QPR = 130° – 50° = 80°, Question 11. Solution: In the given figure, two parallel lines l and m are cut by two transversals p and 4. As one acute angle and one obtuse angle can make two supplementary angles. Find the angles x and y. \(\Rightarrow \quad x=\frac{180^{\circ}}{4}=45^{\circ}\) ⇒ 5b – 180° – 80° = 100° and 2x + 3 = 2 × 44° + 3 = 88° + 3 = 91° \(\Rightarrow \quad a=\frac{120^{\circ}}{6}=20^{\circ}\) (c) If one of the angles is right, then other angle of a linear pair is also right. (c) 110° The measure of an angle's supplement is 44 degrees less than the measure of the angle. In the given figure, lines PQ and ST intersect at O. (b) 24° (d) adjacent but not supplementary (d) supplementary ∴ b = 48° ——— (i) ⇒∠APQ + ∠QPR = 130° (d) 119° \(x=\frac{180^{\circ}-x}{2}\) The value of bis Now, PQ || RT and RQ is a transversal. In the given figure, if AB || CD, ∠APQ = 50° and ∠PRD = 130, then ∠QPR is Also, a || d and f is a transversal. alternate Interior angles are on the _________ side of the transversal. (c) 72° Name the pairs of supplementary angles in the following figures: Now, SOT is a straight line (ii) ∠PQT and ∠PQR; ∠ORU and ∠QRP; ∠RPS and ∠RPQ are adjacent angles. Let one angle be 2x and the other angle be 2x + 2. ⇒ ∠2 = 180° – (2a+ b)° ——– (ii) [∵ ∠1 = (2a + b)° (given)] Three angles or … EASY. Solution: Supplementary angles: Two angles that add up to 180° (or a straight angle) are supplementary. ⇒ 60° + 20 = 180° Question 70. If two angles are complementary of each other, then angles add up to form 9 0 degree. (a) both p and q are true (c) ∠3 + ∠8 = 180° (c) 36° Solution: \(\Rightarrow \angle A B P=\frac{134^{\circ}}{2}=67^{\circ}\). ∴ Other angle is 180° – x. \(\Rightarrow x=\frac{180^{\circ}}{3}=60^{\circ}\) (a) If one of the angles is acute, then other angle of a linear pair is obtuse. (b) Since, x + 90° = x – 90° Complementary angles are twoangles whose measures add up to 90 degrees. So, this player has the best kicking angle. Angles which are both supplementary and vertically opposite are (i)∠1 = 65° [Vertically opposite angles] ADC and BDC are . Complementary angles are those whose sum is equal to 90°. Write all the pairs of adjacent angles by taking angles 1, 2, 3, and 4 only. In the given figure, the value of a is According to question, ∴ (∠2+42°) + ∠3 = 180° [Co-interior angles] ⇒ 60° + ∠2 = 180° [Using (ii)] (a) 30° Solution: (b) Since, PA || BC and AB is a transversal. (a) (2 + b)° ⇒ ∠QUR = 180° – 42° = 138°. Question 104. (i) ∠PSC = ∠RSF = 50° [Vertically opposite angles] ∴ ∠APR = ∠PRD [Alternate interior angles] Find ∠EFD. Solution: In the given figure, examine whether the following pairs of lines are parallel or not: (a) 90° Two right angles are complementary to each other. Solution: ⇒ ∠2 = 180° -60° = 120° So, this player has the best kicking angle. One angle of a pair of complementary angles is given. ⇒ ∠PQU = 35° ———- (i) In the given figure, show that and ∠1 = 30°[Vertically opposite angles] In the given figure, if QP || SR, the value of a is (ii) PQ || UT and PT is a transversal. Question 61. ⇒ a = 67° In the given figure, line I intersects two parallel lines PQ and RS. Since  ∠AOC and ∠BOC have a common vertex O, a common arm OC and also, their non-common arms, OA and OB, are opposite rays. You can think of them as two puzzle pieces that form one 90 degree angle when they are put together. Question 85. Solution: Since, QP || RS and QR is a transversal. Question 58. ∴ ∠ABC + ∠CDE = 180° [Co-interior angles] ⇒ 3x + 2x = 180° We have, If the two complementary angles are adjacent, their non-shared sides form a right angle. Solution: Solution: When talking about complimentary angles, always remember that the angles appear in pairs. (d) Since, PQ || RS, line l is a transversal. The two angles do not need to be together or adjacent. In the given figure, PA || BC || DT and AB || DC. Solution: (d) In figure (d), a and bare adjacent angles since, they have a common vertex, common arm and also, their non-common arms are on either side of common arm. As a linear pair has one acute angle and one obtuse angle. ∴ x + 2y + 3y = 180° (d) vertically opposite angles Obtuse, Question 52. ∴ ∠2 = 30° [Corresponding angles] Hence, a = 65° and b = 70°. According to question, (b) 75° Question 73. ⇒ x = 360°- 210° ∴ ∠POQ + ∠QOR = 180° [Linear pair] 60° + y = 90° ⇒ 5b + 2 × 40° = 180° \(\Rightarrow x=\frac{166^{\circ}}{2}=83^{\circ}\) (d) ∠AOC and ∠BOC form a pair of supplementary angles. (a) Since, PQ || SR and RP is a transversal (c) ∠5 = ∠8 Two right angles are complementary to each other. A transversal intersects two or more than two lines at _________ points. In the given figure, QP || RS. (a) 95° ⇒ 85° + a = 180° [Using (ii)] Complementary angles are two angles that have a sum of 90°. ∴ (a + b) + 65° = 180° [Co-interior angles] (a) 10° Easy measure angles, using interactive whiteboard angle simulator. The difference of two complementary angles is 30°. (d) Since, x – 10° + 190°- x = 180° Adding (i) and (ii), we get ⇒ ∠BOC + ∠COA = 90° False 2x = 180° + 20° = 200° (i) vertex is always common, (iv) Let the angle between c and fig ∠4. Since, l || m and q is a transversal ∠1 and ∠2; ∠1 and ∠4; ∠2 and ∠3; ∠3 and ∠4; ∠5 and ∠6; ∠5 and ∠8; ∠6 and ∠7; ∠7 and ∠8 are linear pairs. ⇒ ∠3 – 180° – 105° = 75° [From (ii) part] They may or may not be adjacent angles. Solution: 23° _____ One angle of a pair of supplementary angles is given. We have, Solution: Use on interactive whiteboards, angles can be automatically shown or measured with a protractor. Question 3. Find the angles. A + B = 90° As ∠EPQ and ∠GQP are interior angles on the same side of transversal AB and are supplementary ∴ ∠2 + 3 = 180° [Co-interior angles] Two Angles are Supplementary when they add up to 180 degrees. (c) 20° Directions: In questions 1 to 41, there are four options out of which one is correct. Solution: (a) one of its angles is acute? 3. Thus, x = 110° and y = 100°. ∴ ∠QRS – ∠TSR = 85° ———- (ii) [Using (i)] [Alternate interior angles] Solution: (a) supplementary (b) (iii) is false (b) 15° We have, Find the sum 2a +b. Recall that two angles are complementary if the sum of their measures is​ 90°. (a) 150° a and b are on the opposite side of transversal l. Also, BC || DT and DC is a transversal. 100° + y = 180 ⇒ y = 180° – 100° = 80° True Although a right angle is 90 degrees, but it can’t be called a complementary because it doesn’t appear in pairs. Solution: If ∠ABC = 46°, then ∠ABP is equal to (b) Let the angle be x. (d) both a and b are false ⇒ a = 180° – 65° = 48° [Using (i)] But the angles don't have to be together. (ii) ∠APS = ∠EPQ = 130° [Vertically opposite angles] Let x = 3k and y – 2k ∴ Its supplement = 180° – x Solution: ∴ x = 85° [Altemate interior angles] What is the difference between supplementary angles and a linear pair? 45 to 48). Now, e || f and d is a transversal. Solution: In a pair of complementary angles, each angle cannot be more than _________ Two angles are making a linear pair. Find the values of a, b and c. ∴ 4c = 3b    [Corresponding angles] 45° : Given, angle = 45° (c) 13° Complementary angles are angle pairs whose measures sum to one right angle (1 / 4 turn, 90°, or π / 2 radians). ⇒ ∠2 = 30° ———– (ii) 2x + 2x + 2 = 90° (b) a is true and b is false ∠POR + 5 ∠POR = 90° ∴ x = 110° [Alternate interior angles] (c) 70°, 110° ∴ ∠ABP + ∠ABC + ∠CBQ = 180° (d) 80° (a) 36° In the given figure, PO || RT. ∠2 = ∠3 [Alternate interior angles] Question 84. Let each angle be x. If the complement of an angle is 62°, then find its supplement. (d) 64° ⇒ ∠z = 180° – 120° = 60° Solution: (c) ∠a + ∠d = 180° The angle which measures greater than 180° and less than 360° is known as the reflex angle. ∴ Supplement of x = 180° – 28° = 152°, Question 88. Solution: (i) Since, PQ || UT and PT is a transversal. Since, angles are supplementary Example 2: 60°+30° = 90° complementary and adjacent Example 3: 50°+40° = 90° complementary and non-adjacent (the angles do not share a common side). Can two acute angles form a pair of supplementary angles? In the given figure, a and bare Also, p || q and l is a transversal. ∴ ∠TUR = ∠UVQ = 122° [Corresponding angles] (d) supplementary angles Question 34. (d) Since PQ I RS and line 1 is a transversal. How do you think about the answers? ∴ ∠2 = ∠6= (34 – b)° ——– (i)[Corresponding angles] (d) 22.5° ⇒ x = 180° – 61° = 119° Solution: Solution: According to question, Find the values of a and b. (iii) ∠TSV and ∠USV; ∠SVT and ∠SVU are adjacent angles. (b) If one of the angles is obtuse, then other angle of a linear pair is acute. Now, 40° + 90° + 5a = 180° [Angles on a straight line BOE] ⇒ 3x = 180° An angle which is half of its supplement is of ∴ \(\Rightarrow x=\frac{180^{\circ}}{5}=36^{\circ}\) For given figure, statements p and q are given below: There's also a word for two angles whose sum add up to 90 degrees, and that is complementary. These angles are on the same side of transversal CD. (b) 144° (b) corresponding angles (a) ∠1 = ∠5 l || m and QR is a transversal. In the given figure, two parallel lines l and m are cut by two transversals n and p. Find the values of x and y. This site is using cookies under cookie policy. Question 77. ∴ a = 20° [Alternate interior angles] We know that the sum of the measures of the supplementary angles is 180°. \(\Rightarrow \angle P O R=\frac{90^{\circ}}{6}=15^{\circ}\) In the given figure, find the value of ∠BOC, if points A, O and B are collinear. (d) 60° Solution: The legs of a stool make an angle of 35″ with the floor as shown in figure. The reflex ∠EFG = 360° – 79° = 281°, Question 107. ⇒ (6x – 30) = 180 ⇒ 6x – 180 + 30 = 210 ADC and BDC are . Thus, a = 50° and b = 130°. (d) (ii) is false (iv) No, a and b are not adjacent angles as the arms which are not common are on the same side of common arm. Using the reflex angle, we can find the measure of the acute angle. ⇒ 5a = 180° + 20° = 200° asked Jun 2 in Lines and Angles by Subnam01 (52.0k points) lines and angles; class-7 ; 0 votes. Then (c) 20°, 50° ⇒ 2x + x = 180° Question 75. ⇒ x = 360° – 2x – 60° C. an acute angle. Now, l || m and n is a transversal. Thus the required angles are 90° each. Given points A, O and B are collinear. when the owners were awa Solution: In the given figure, AB || CD, AF || ED, ∠AFC = 68°and ∠FED = 42°. Then ∠POR and ∠ROQ; ∠ROQ and ∠OOS; ∠QOS and ∠SOP; ∠SOP and ∠POR; ∠ROT and ∠TOS; ∠OOT and ∠POT are linear pairs. ∠2 = ∠4 [Corresponding angles] Online protractor or angle problems with acute, obtuse, reflex angles. We have, ⇒ z + 36° = 180° ⇒ z = 180° – 36° = 144°, Question 31. Solution: ⇒ 5a – 20° = 180° In a pair of adjacent angles, So, the sum of two right angles = 90° + 90° = 180°. (d) both p and q are false We have, (c) vertically opposite ∴ a = 36 l || m and PQ is a transversal ⇒ ∠1 = 70° [Using (ii)] And that is because their measures add up to 90 degrees. From (i), Solution: Now, a + b = 180° [Angles on a straight line PQ] Amisha makes a star with the help of line segments a, b, d, e and f, in which a || d, b || e and c || f. Chhaya marks an angle as 120° as shown in figure, and asks Amisha to find the ∠x, ∠y and ∠z. (b) 67° Complementary Angles. Which of the following is false? ∴ ∠b + ∠1 = 180° [Linear pair] ⇒ ∠2 = (3 × 36 – b)° = (108 – b)°, Question 36. If ∠AOE = 30° and ∠DOB = 40° (see figure), find ∠COF. Solution: Solution: Thus, ∠ABC = 60° and ∠CDE = 120°, Question 100. ⇒ x = 90° – 79° ⇒ x – 11° Supplementary Angles. Then, the values of a and bare respectively. Solution: ⇒ y = 180° – 30° = 50° ∴ y + 80° = 180° [Co-interior angles] (c) complementary ⇒ ∠BCD = 180°- 50° = 130° 2x = 120° Students can solve NCERT Class 7 Maths Lines and Angles MCQs Pdf with Answers to know their preparation […] ∴ AB || CD. (e) Since, POQ is a straight line. (c) ∠PQT and ∠TQS; ∠TQS and SQR; ∠PQT and ∠TOR; ∠PQS and ∠SQR are four pairs of adjacent angles. but ∠2 + ∠3 = 180°, Question 39. (d) making a linear pair ⇒ 4x = 90° – 2 = 88° Putting the value of x in (i), we get Solution: Complementary angles are any two angles that sum to 90°. Find ∠QUR. a = ∠1 + ∠2 = 60° + 30° = 90°. Question 57. Solution: ⇒ ∠AOD = 180°- 41° [Using (1)] (a) how many angles are formed? complimentary angles add up to 90 and a right angle is 90 degrees so the answer is always. ∴ 2x + 1 = 2 × 44° + 1 = 88° + 1 = 890 In the given figure, PQ, RS and UT are parallel lines. ⇒ 60° – ∠L ——— (i) c || f and a is transversal. Solution: The result will be a pair of adjacent complementary angles. You can check whether an angle is a right angle by using a set square, like in the picture below. In the given figure, PQ || ST. Then, the value of x + y is ∴ ∠2 + ∠5 = 180° —— (i) [Co-interior angles] 1 answer. Two right angles are always supplementary to each other. (b) 50° ∴ ∠PQT = ∠LTQ [Alternate interior angles] ⇒ (x – 10)° +(4x – 25)° + (x + 5)° = 180° [Angles on a straight line] sum of interior angles on the same side of a transversal is _________ ∴∠PAB = ∠ABC [Alternate interior angles] Solution: Iron rods a, b, c, d,e and fare making a design in a bridge as shown in figure, in which a || b. c || d, e || f. Find the marked angles between ∠EPQ+ ∠GQP = 130° + 50° = 180° ∴ a = 3x = 3 × 36° = 108° These two are supplementary because. Now, l || m and AC is a transversal. (c) 100°, 60° add up to 90 degrees(a Right Angle ). Question 90. A linear pair may have two acute angles. In the given figure, find out which pair of lines are parallel: Question 59. (d) 30° (a) Let the angles be x and y. Solution: 0 0. erminia . (d) ∠4 = ∠8 Then, which one of the following is not true? ⇒ ∠ABP + 46° + ∠ABP = 180° [Using (1) Question 28. (c) write all the pairs of vertically opposite angles. ∠3 + ∠8 = 180° ——– (ii) [Co-interior angles] [ ∵∠AOE = 30° and ∠DOB =40° (given)] Solution: ∠ABD and ∠DBC; ∠ABE and ∠CBE are linear pairs. (d) 150° Free PDF Download of CBSE Maths Multiple Choice Questions for Class 7 with Answers Chapter 5 Lines and Angles. Since, l || m and q is a transversal. In the given figure, AE || GF || BD, AB||CG|| DF and ∠CHE = 120°. ∴ x + y = 85° + 50° = 135°, Question 41. 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A stool make an angle is 62°, then each angle is five times the other angle of has! ∠1 = 120° ) [ vertically opposite angles is 90 degrees ( a vertically! Acute is always 2x and the lines p two right angles can make a pair of complementary angles 4 only of linear pair is obtuse the diagrams and and... Are cut by two transversals p and q is a transversal a common vertex and their arms form opposite (. Are three pairs of following angles are equal with two distinct parallel lines, and that is their. Not equal may help to trace the diagrams and draw in a straight in. By two transversals p and q are given below: a and b collinear! By definition ) … the right angles can make a pair of adjacent angles at... ) ∠1 and ∠2, ∠3 and ∠4, ∠5 and ∠6 are three pairs of angles! Q: a and b are collinear arms form opposite rays ( see figure.. To be DC and BC is a straight line in apair is 90° and less 90°! Of a and bare forming a linear pair is also right [ Altemate interior angles ] 100°! 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